1/3 ln (x) - 1/5 ln y
5 ( p - 2 ) - 2 ( 3p + 4 )
(1331*x^2 + 121*x + 11)/(x - 1)
find value of x
(0.5m^2)/(0.770+0.05m)
2(m + 40) - 6m = 3 (4m - 80 )
0.5m/(0.770x0.05)
y = - $\frac{3}{2}$ x - 1
x = -3
what is the y value
What is the mass of 1.20 x 10^21 atoms of sulfur?
1.20 x 10^21 / (6.02 x 10^23)
