3y_x=5
5y-2x=1
3y+8x=22
y+6x=9
7x-6y=30
2x+6y=24
Ali had some marbles. He could group them into sets of 5 marbles or sets of 8 marbles without leaving any remainder. However, when...
how to solve this pattern 2,4,8,3,5,14,4,6,22,7,9,_______?
2x+3y=8
3x+4y=11
if x+y+3z=0, then find the following equation (((x+y)^2)/3xy) + (((y+3z)^2)/9yz) + (((3z+x)^2)/9xz)
I=∫(x 2+3x+2)dx
3x^6+5x+7
x^4+8y+5
(x^3 + 2x + 1)/5 – (7/2)x^2 – x^6,
