(x^3 + 2x + 1)/5 – (7/2)x^2 – x^6,

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on Feb 01, 2025 at 1:06 am



You asked:

Evaluate the expression: x3+2x+15−72x2−x6\frac{{x}^{3} + 2 x + 1}{5} - \frac{7}{2} {x}^{2} - {x}^{6}

MathBot Answer:

Evaluated



x3+2x+15−72x2−x6=−x6+x35−7x22+2x5+15\displaystyle \frac{{x}^{3} + 2 x + 1}{5} - \frac{7}{2} {x}^{2} - {x}^{6} = - x^{6} + \frac{x^{3}}{5} - \frac{7 x^{2}}{2} + \frac{2 x}{5} + \frac{1}{5}

Expanded

x3+2x+15−72x2−x6=−x6+x35−7x22+2x5+15\frac{{x}^{3} + 2 x + 1}{5} - \frac{7}{2} {x}^{2} - {x}^{6} = - x^{6} + \frac{x^{3}}{5} - \frac{7 x^{2}}{2} + \frac{2 x}{5} + \frac{1}{5}

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