integral of sqrt(x) from x = 0 to x = 10
|0.7x+5|>6.7
$$\sum_{a}^{b}{C}$$
C=((3x-1)^a) / ((a^3)+a)
b= $\infty$
a=0
sin4theta - cos4theta upon sintheta - cos theta = sintheta + cos theta
.177 รท 1.6
16/4(3-5)
$$\sum_{a}^{b}{C}$$ ((3x-1)^a) / ((a^3)+a)
3(8-y)=-(y-4)
27 5/9-18 7/9=
5(8-y)=-(y-4)