(2a+3b) ^5
asked by guest on Apr 06, 2025 at 10:21 am
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MathBot Answer:
(2a+3b)5=(2a+3b)5{\left( 2 a + 3 b \right)}^{5} = \left(2 a + 3 b\right)^{5}(2a+3b)5=(2a+3b)5
(2a+3b)5=32a5+240a4b+720a3b2+1080a2b3+810b4a+243b5{\left( 2 a + 3 b \right)}^{5} = 32 a^{5} + 240 a^{4} b + 720 a^{3} b^{2} + 1080 a^{2} b^{3} + 810 b^{4} a + 243 b^{5}(2a+3b)5=32a5+240a4b+720a3b2+1080a2b3+810b4a+243b5