850000x=1
2x+5y=1
$x^{2}$ +5xy- $4y^{2}$ +10=0
log(2.5*10^-6)
-log(2.5*10^-6)
$-41x^{2}$ +41x+6=0
log(2.5*10-6)
-66y-41=0
87.6 divided by 0.12
the middle 95% of the standard normal distribution is bound by the z values
6 divide by x gives 3.14 what is x
x(8-x) + 33
