25y$^2$-9x$^2$
lcm of 14.5 and 5.5
16p$^2$-25
prove that cot/1+tanθ=cotθ-1/2-sec²θ
25a$^2$-4
-11+x=-5+x
9n$^2$-1
16k$^2$-9
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If P=(4,-1) is the midpoint of the segment AB, where A(2, 5), find B.