(2x-1/2)2
asked by guest on Jan 14, 2025 at 2:29 am
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MathBot Answer:
(2x−12)⋅2=4x−1\displaystyle \left(2 x - \frac{1}{2}\right) \cdot 2 = 4 x - 1 (2x−21)⋅2=4x−1
(2x−12)⋅2=4x−1\left(2 x - \frac{1}{2}\right) \cdot 2 = 4 x - 1(2x−21)⋅2=4x−1