I+V = VI
((n+1)/(n^2+3n+1))-((n)/(n^2+n-1))
2p^2-4px+5pj=3x^2+x-8 if the products of the roots equals twice the sum.
(5/7+2/3) =
((n+1)/(n^2+n-1))-((n)/(n^2+n-1))
1+5
z = x-iy/x+iy then |z|
456 = CCCCLVI
78628÷9
