consider the curve x=t^3-3t and y=t^2. calcuate dy/dx
Surface area of a sphere = 4*pi*radius^2
8+ (-3)
30รท5*2+13-45=
8Y+8Y = 0
8=(-3)
Find the square root of
1
โ
3
๐
1โ
โ
i using De Moivre's Theorem.
using the inequaluities
1/2<2/3
3/4<4/5
5/6<6/7
prove that
1/2*3/4*5/6<1/ $\sqrt{\Box}$...
1.24x10-2
0.20ร10-2
$\frac{0.5z}{(z+0.2)^{2}(z+1.1)}$