$\frac{0.5z}{(z+0.2)^{2}(z+1.1)}$

asked by guest
on Oct 24, 2024 at 7:20 am



You asked:

Evaluate the expression: \(\frac{0.5 z}{{\left( z + 0.2 \right)}^{2} \cdot \left(z + 1.1\right)}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{0.5 z}{{\left( z + 0.2 \right)}^{2} \cdot \left(z + 1.1\right)} = \frac{z}{2 \left(z + \frac{1}{5}\right)^{2} \left(z + \frac{11}{10}\right)} \)


Expanded

\[\frac{0.5 z}{{\left( z + 0.2 \right)}^{2} \cdot \left(z + 1.1\right)} = \frac{z}{2 z^{3} + 3 z^{2} + \frac{24 z}{25} + \frac{11}{125}}\]


Factored

\[\frac{0.5 z}{{\left( z + 0.2 \right)}^{2} \cdot \left(z + 1.1\right)} = \frac{125 z}{\left(5 z + 1\right)^{2} \cdot \left(10 z + 11\right)}\]