(3x-7)[3(x+1)-2(x+3)]-2x(x+6)=
19-16* $\frac{\8}{\5}$
17-16* $\frac{\6}{\5}$
(3x-7)[3(x+1)-2(x+3)]-2x(x+6)
593/2
18-16* $\frac{\7}{\5}$
20000-50
x³+x=1 x=?
6a+7ab,2a+3b
