(1.04/2)*x = 350
(a3a^{3}a3+b3b^{3}b3+c3c^{3}c3)=?
( a3a^{3}a3 + b3b^{3}b3 + c3c^{3}c3 )
rearange the equation to make I the subject
G= i2i^{2}i2 R
note: please only consider the positive square root
( a3a^{3}a3 + a3a^{3}a3)
G=I a2a^{2}a2 R
x3
√2 upon 2√2
factorize fully
100axsquared +65axy -75ay squared
14 x 14
