( a3a^{3}a3 + b3b^{3}b3 + c3c^{3}c3 )
asked by guest on Mar 29, 2025 at 3:39 am
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MathBot Answer:
a3+b3+c3=a3+b3+c3{a}^{3} + {b}^{3} + {c}^{3} = a^{3} + b^{3} + c^{3}a3+b3+c3=a3+b3+c3