in
411 Data Analysis in Communication Researcho= Constant, where using law 4 of indices state anything raised to the power of 0 = 1Sn...
60-{16÷(4×6-8)}
19=3x+4
13=5x-7
(5k -2)(5k + 2) - (1 - k)(1+k)
12r-15=21
Iam giving you an equation
Vcos¢\g [vsin¢+(√2gh+v^2sin^2¢)]
here v= ...
5*2-(84/6(12-5))/2
