Determine the angle between lines of intersection of the plane x-3y+z=0 and the quadratic cone x²-5y²+z²=0
\dfrac{185}{100} + 50\% + 4\% =
x<y<0<z
|y-x|+|y-z|+|z-x|-|z-y-x|
A) x+y
B) y-x+z
C) z-y
E) z+y
(√5-√2) (√5+√2)
4x(1/2)
d $a_{b}$ dx sinx
a^{1/3}^{2}
(2*n+1)*(4*n+1)
kako izgleda kruznica x^2 + (y-2)^2 = 1
Derivatives
