(4w - 1)(2w^2 - 2w + 1)

asked by guest
on Apr 07, 2025 at 9:53 am



You asked:

Evaluate the expression: (4w−1)(2w2−2w+1)\left(4 w - 1\right) \left(2 {w}^{2} - 2 w + 1\right)

MathBot Answer:

Evaluated



(4w−1)(2w2−2w+1)=(4w−1)(2w2−2w+1)\displaystyle \left(4 w - 1\right) \left(2 {w}^{2} - 2 w + 1\right) = \left(4 w - 1\right) \left(2 w^{2} - 2 w + 1\right)

Expanded

(4w−1)(2w2−2w+1)=8w3−10w2+6w−1\left(4 w - 1\right) \left(2 {w}^{2} - 2 w + 1\right) = 8 w^{3} - 10 w^{2} + 6 w - 1

+ Submit Question