2+2
By making an appropriate substitution, we find that the value of ∫1/5−1/5(5x+2)11dx
is:
Question 1Answer
A.
132,8603
...
23-45-4444-43
35+-5(-3x+2)
3000 x 0.6
$153.8^{0.45}$
$153.8^{2.2}$
$153,8^{2.2}$
