$$\begin{bmatrix} -6 & 1 \\\\ 9 & 2 \end{bmatrix}$$ $$\begin{bmatrix} 3 & 0 \\\\ -3 & 4 \end{bmatrix}$$
differentiate first principle y=x^2-4x
solve for a
a-1=a^2+1
-4 $$\begin{bmatrix} 1 & 10 \\\\ -4 & -6\end{bmatrix}$$ - $$\begin{bmatrix} 4 & 8 \\\\ -3 & -8 \end{bmatrix}$$
0.25 $$\begin{bmatrix} 8 & 20 & -12\\\\ -8 & -4 & 36 \end{bmatrix}$$
$$\begin{bmatrix} 2 & 5 & -4 \\\\ 3 & 0 & -2 \end{bmatrix}$$ + $$\begin{bmatrix} 3 & 2 & 7 \\\\ -2 & -5 & 7 \end{bmatrix}$$
(x - 1) (x + 1) = (x-1)^2
2b 2 c 2 +2c 2 a 2 +2a 2 b 2 −a 4 −b 4 −c 4
(x - 1) (x + 1) = Hx - 1L2
2 5 -4 + 3 2 7
3 0 -2 -2 -5 7
