(x - 1) (x + 1) = Hx - 1L2

asked by guest
on Jan 14, 2025 at 6:36 pm



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$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

$(x - 2)(x + 1) = 3x - 2$

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