$12-\frac{1}{5}r=2r+1$
cual es el volumen de la caja si x es igual a 5
1.732-0.8391
12-\dfrac{1}5r=2r+1
-0.4337x + 48.744 = 2.0975x - 20.596
-0,4337x + 48,744 = 2,0975x - 20,596
-f+2+4f=8-3f
$\frac{x}{5}$ = -3
(100+10)(6283)/(100+1.1)
d - 6 = -4
