Dados os vetores πβ=(β1,1,2) e πββ=( 2,0,4), determine o vetor π£β, tal que:
2
3
π£β β [2(π£β + πβ) β πββ] =
πββ
4
β
π£βββπββ
3y+2=\sqrt{y^2+10y+7}
126/197
197/126
logβ(1 - 2x) - logβ(1 + 4x) = -1
Find the value of x.
CombinaciΓ³n lineal de los vectores: v1 = (1, 2, 1); v2 = (3, 5, 6); v3 = (4, 7, 5), y los escalares x1 = -3, x2 = -1 y X3 = 2
9712
2x-3y=14
-x+2y=-8
16.66Γ·25
