The circumference of the circle is 22 cm. What will be its area?
112+5⁴
8/9-2/3
From Equation (1):
\[\sigma_r = \nu \sigma_t + E \cdot \frac{du}{dr} - E \cdot \alpha T \tag{3}\]
F(u,v)=sen(uv2)/v−3
\[E \cdot \frac{du}{dr} - \sigma_r + \nu \sigma_t = E \cdot \alpha T \tag{1}\]
\iint \exp{\left(-x^4-y^4-x^2y^2\right)}\,dx dy
Y = x^2 + 4x +3
y= x^2-6x+8
whats the porabula
the tempriture
g(x)= log(x+2)
