solve k*(200000^a)*(80^b) = 99.29,
k*(200000^a)*(50^b) = 29.40,
k*(200000^a)*(200^b) = 1200
for k, a, b
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
solve k*(200000^a)*(80^b) = 99.29,
k*(200000^a)*(50^b) = 29.40,
k*(200000^a)*(200^b) = 1200
for k, a, b
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.