|4x-4|=16
3dn+4nd+7dn = 14dn
|4x+2|=12
\((-b\pm \sqrt{b^{2}-4ac})/(2a)\)
a=6-3
|2x+1|=9
|3x+3|=18
2(a+b)(a-c)
2y^2-11y+12=0
Given that y is inversely proportional to 𝑥^2
, how is y affected if x is halved?
