(−b±b2−4ac)/(2a)(-b\pm \sqrt{b^{2}-4ac})/(2a)

asked by guest
on Nov 19, 2024 at 7:24 am



You asked:

Evaluate the expression: −b±b2−4ac2a\frac{-b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}

MathBot Answer:

This question involves the ±\pm operator. There are 22 variations to solve.

Variation 11 of 22

−b+b2−4ac2a=−b2a+−4ac+b22a \frac{- b + \sqrt{b^{2} - 4 a c}}{2 a} = - \frac{b}{2 a} + \frac{\sqrt{- 4 a c + b^{2}}}{2 a}

Variation 22 of 22

−b−b2−4ac2a=−b2a−−4ac+b22a \frac{- b - \sqrt{b^{2} - 4 a c}}{2 a} = - \frac{b}{2 a} - \frac{\sqrt{- 4 a c + b^{2}}}{2 a}

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