El punto terminal sobre el círculo unitario del número real t=−23π2
es:
Question 2Select one:
(0,1)
(−1,0)
(0,−1...
(a+b)-4ab
(7*8+1)
7* 10∗10−6\sqrt{10*10-6}10∗10−6 -(7*2*2*2+8°)/3
|8x + 16| − |4x + 8| = 8
7* 10∗10−6\sqrt{10*10-6}10∗10−6 -(7*2*2*2+8)/3
t+15d/dt = 0
a/6 + 2a/9
Evaluate
(
−
3
7
)
÷
5
4
(−
)÷(−
Enter your answer as a fully simplified fraction.
