Make z the subject of
x=y-z
15-2+8+10=
mdas rule
The polynomial of degree 3, P(x), has a root of multiplicity 2 at x=2 and a root of multiplicity 1 at x=-5. The y-intercept is y=4...
Make x the subject of
$\sqrt{x+3}$ =m
The roots of 1/(x-3)-1/(x+5)=1/6 are:
(-3)+(-2)-(+5)
mn(5x+1)-pq(5x+1)
0.125=0.408*e^-75x