find x: 9^(2x+y)=81^(x-2)/3^x

asked by guest
on Nov 24, 2024 at 1:36 pm



You asked:

Solve the equation 92x+y=81x−23x{9}^{2 x + y} = \frac{{81}^{x - 2}}{{3}^{x}} for the unknown xx.

MathBot Answer:

x=log⁡(3−2y6561)log⁡(3)∧−∞<x∧x<∞x = \frac{\log{\left(\frac{3^{- 2 y}}{6561} \right)}}{\log{\left(3 \right)}} \wedge -\infty < x \wedge x < \infty

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