find x: 9^(2x+y)=81^(x-2)/3^x
You asked:
Solve the equation \[{9}^{2 x + y} = \frac{{81}^{x - 2}}{{3}^{x}}\] for the unknown \(x\).
MathBot Answer:
\(x = \frac{\log{\left(\frac{3^{- 2 y}}{6561} \right)}}{\log{\left(3 \right)}} \wedge -\infty < x \wedge x < \infty\)