x+y less than 5
x-y=2a, ax+by=$a^{2}$+ $b^{2}$ then
find the value of x and y
3ab-5b+3ac+4by
integral(z-z^2 )where cisahalfcircisahalfcircle|z -2|=3
3r^2-4r-6 / 5r^2-16r+3
x-y=2a, ax+by=a\power{2}+b\power{2} then
x-y=2a-----[1]
ax+by=a\power{2}+b\power{2}-----[2]
ax-4ay-bx+4by
x^2[x^-0.5]
Tiffany runs 3/4 mile on Tuesday and 1/2 mile on Wednesday. How many total miles did she run?
