7/6*2/5
If y= a cos (log x) + b sin(log x), then show that x2 yn+2 + (2n+1)xyn+1 + (𝑛
2 + 1) yn = 0
y+4=0
find [AB] in A(2,5) and B(10,8)
7 2/3 + 5 3/7 =
((2.48*10^-3)*x)^2+(460.8)^2+(1645.71)^2-(1645.71-460.8)*((2.48*10^-3)*x)+(460.8)*(1645.71)=2500^2
y=(x+1)²
25/18
y=(x+2)²
12 - 4m < 5 -8m
