d(x,-2)>1
x + y = 4 $\sqrt{\3}$
47°31´+78°56´+X=180°
find the sequence of the 13th term
1+8/2
$\frac{x^2-14x+40}{x^2-6x+8}$
2/5+7 -1/2*8=
180°-47°31´-78°56´=
(x+4)(x
2
−3x+2)=x(x
−3x+2)+4(x
−3x+2)
Simplify the following expression completely.
