$\frac{x}{\sqrt{x^2+1}}$

asked by guest
on Nov 28, 2024 at 1:49 pm



You asked:

Evaluate the expression: \(\frac{x}{\sqrt{{x}^{2} + 1}}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{x}{\sqrt{{x}^{2} + 1}} = \frac{x}{\sqrt{x^{2} + 1}} \)


Expanded

\[\frac{x}{\sqrt{{x}^{2} + 1}} = \frac{x}{\sqrt{x^{2} + 1}}\]