((h-1)/(h+1)+(h+1)/(h+1))/((h-1)/(h-1)-(h+1)/(h-1))
asked by guest
on Jan 28, 2025 at 2:39 pm
You asked:
Evaluate the expression:
h−1h−1−h−1h+1h+1h−1+h+1h+1
MathBot Answer:
Evaluated
h−1h−1−h−1h+1h+1h−1+h+1h+1=1−h−1h+1h+1h−1+1
Expanded
h−1h−1−h−1h+1h+1h−1+h+1h+1=−h−1h2+h−h−12h+1−h−11h−−h−1h2+h−h−12h+1−h−111+−h−1h+1−h−111
Factored
h−1h−1−h−1h+1h+1h−1+h+1h+1=−h+1h(h−1)