𝑒^2𝑥 − 𝑒𝑥 = 20

asked by guest
on Nov 21, 2024 at 2:11 am



You asked:

Investigate the equation: e2x−ex=20{e}^{2} x - e x = 20.

MathBot Answer:

The solution is: x=20(−1+e)e≈4.2819453x = \frac{20}{\left(-1 + e\right) e} \approx 4.2819453

x(−e+e2)=20x=20−e+e2\begin{aligned}x \left(- e + e^{2}\right) &= 20\\x &= \frac{20}{- e + e^{2}}\end{aligned}

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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