\frac{1}{\frac{1}{1000}+\frac{1}{800}}=x
You asked:
Solve the equation \(\frac{1}{\frac{1}{1000} + \frac{1}{800}} = x\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{4000}{9} = 444.\overline{4}\]
\[\begin{aligned}\frac{4000}{9} &= x\\- x &= - \frac{4000}{9}\\x &= \frac{4000}{9}\end{aligned}\]