find the equation of the line with the slope equal to 1/2 and passing through (5,-3)
You asked:
Find an equation of the line through the point \((5, -3)\) with slope \(\frac{1}{2}\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{1}{2} \\ A =& -1, B = 2 \end{aligned}$$$$\begin{aligned}-1 x + 2 y + C &= 0 \\ -1(5) + 2(-3) + C &= 0 \\ -5 + -6 + C &= 0 \\ -5 + C &= 6 \\ C &= 11 \end{aligned}$$An equation of the line in standard form is: $- x + 2 y + 11 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= \frac{1}{2}x + b \\ -3 &= \frac{1}{2} \times 5 + b \\ -3 &= \frac{5}{2} + b \\ b &= - \frac{11}{2} \end{aligned}$$The slope-intercept form of the line is: $y = \frac{x}{2} - \frac{11}{2}$.