$$\int_{0}^{4}(x/( x^2 -9)) dx
You asked:
Evaluate the integral: \(\int_{0}^{4}{\frac{x}{{x}^{2} - 9}}dx\)
MathBot Answer:
Definite integral
\[\int_{0}^{4}{\frac{x}{{x}^{2} - 9}}dx = \text{NaN}\]
You asked:
MathBot Answer:
\[\int_{0}^{4}{\frac{x}{{x}^{2} - 9}}dx = \text{NaN}\]