22ª- 36(2)+128 = 0

asked by guest
on Nov 14, 2024 at 10:52 pm



You asked:

Solve the equation 22a−36⋅2+128=0{22}^{a} - 36 \cdot 2 + 128 = 0 for the variable aa.

MathBot Answer:

The solution is: a=log⁡(56)+iπlog⁡(22)≈1.3022635+1.0163538ia = \frac{\log{\left(56 \right)} + i \pi}{\log{\left(22 \right)}} \approx 1.3022635 + 1.0163538 i

ii is the imaginary unit, defined as i2=−1i^2 = -1.

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