[–4 + (2^2 – 5 · 6)] ÷ (–5 + 2) + 2
You asked:
Evaluate the expression: \(\frac{-4 + {2}^{2} - 5 \cdot 6}{-5 + 2} + 2\)
MathBot Answer:
\[\frac{-4 + {2}^{2} - 5 \cdot 6}{-5 + 2} + 2 = 12\]
\[\begin{aligned}\frac{-4 + {2}^{2} - 5 \cdot 6}{-5 + 2} + 2& = \left(-4 + 2^{2} - 5 \cdot 6\right) \cdot \frac{1}{-5 + 2} + 2\\& = \left(-4 + 4 - 5 \cdot 6\right) \cdot \frac{1}{-5 + 2} + 2\\& = \left(-4 + 4 - 30\right) \cdot \frac{1}{-5 + 2} + 2\\& = \left(0 - 30\right) \cdot \frac{1}{-5 + 2} + 2\\& = -30 \cdot \frac{1}{-5 + 2} + 2\\& = \frac{-30}{-3} + 2\\& = 10 + 2\\& = 12\end{aligned}\]