1/72+1/72+6/8=
You asked:
Evaluate the expression: \(\frac{1}{72} + \frac{1}{72} + \frac{6}{8}\)
MathBot Answer:
\[ \frac{1}{72} + \frac{1}{72} + \frac{6}{8} = \frac{7}{9} = 0.\overline{7} \]
The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{72}\), \(\frac{1}{72}\), and \(\frac{6}{8}\) is \(72\). \[ \begin{aligned} \frac{1}{72} + \frac{1}{72} + \frac{6}{8} &= \frac{1 \cdot 1}{72 \cdot 1} + \frac{1 \cdot 1}{72 \cdot 1} + \frac{6 \cdot 9}{8 \cdot 9} \\ &= \frac{1 + 1 + 54}{72} \\ &= \frac{56}{72} \\&= \frac{7}{9} \end{aligned} \]