8log\left(\frac{A}{B}\right)−6log\left(\frac{B}{A}\right)=log\left(\frac{A^m}{B^n}\right)

asked by guest
on Oct 22, 2024 at 1:45 pm



You asked:

Investigate the equation: \(8 \cdot \log\left( \frac{A}{B} \right) - 6 \cdot \log\left( \frac{B}{A} \right) = \log\left( \frac{{A}^{m}}{{B}^{n}} \right)\).

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