Math Problem Solver

\[ 2\frac{2}{3} + 3\frac{53}{4} = \frac{227}{12} = 18.91\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{2}{3}\), \(\frac{3}{1}\), and \(\frac{53}{4}\) is \(12\). \[ \begin{aligned} 2\frac{2}{3} + 3\frac{53}{4} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{2 \cdot 4}{3 \cdot 4} + \frac{3 \cdot 12}{1 \cdot 12} + \frac{53 \cdot 3}{4 \cdot 3} \\ &= \frac{24 + 8 + 36 + 159}{12} \\ &= \frac{227}{12} \end{aligned} \]