2v^2-14v / 5v^2-35v

asked by guest
on Mar 24, 2025 at 12:36 pm



You asked:

Evaluate the expression: 2v2−14v5v2−35v2 {v}^{2} - \frac{14 v}{5 {v}^{2}} - 35 v

MathBot Answer:

Evaluated



2v2−14v5v2−35v=2v2−35v−145v\displaystyle 2 {v}^{2} - \frac{14 v}{5 {v}^{2}} - 35 v = 2 v^{2} - 35 v - \frac{14}{5 v}

Factored

2v2−14v5v2−35v=10v3−175v2−145v2 {v}^{2} - \frac{14 v}{5 {v}^{2}} - 35 v = \frac{10 v^{3} - 175 v^{2} - 14}{5 v}

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