Find the focus, vertex, equation of directrix and length of the latus rectum of the conic x = y ^ 2 - 4y + 2
You asked:
Find the focus, the vertex, the directrix, and the length of latus rectum of \(x = {y}^{2} - 4 y + 2\)
MathBot Answer:
The focus of the parabola \(x = y^{2} - 4 y + 2\) is at \(\left(- \frac{7}{4}, 2\right)\).
The vertex of the parabola \(x = y^{2} - 4 y + 2\) is at \(\left(-2, 2\right)\).
The directrix of the parabola \(x = y^{2} - 4 y + 2\) is \(x = - \frac{9}{4}\).
The length of the latus rectum of the parabola \(x = y^{2} - 4 y + 2\) is \(1\).