( 5x5^{x}5x - 5x−15^{x-1}5x−1) / (4* 5x−15^{x-1}5x−1 )
asked by guest on Mar 22, 2025 at 7:35 pm
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MathBot Answer:
5x−5x−14⋅5x−1=51−x(5x−5x−1)4\displaystyle \frac{{5}^{x} - {5}^{x - 1}}{4 \cdot {5}^{x - 1}} = \frac{5^{1 - x} \left(5^{x} - 5^{x - 1}\right)}{4} 4⋅5x−15x−5x−1=451−x(5x−5x−1)
5x−5x−14⋅5x−1=1\frac{{5}^{x} - {5}^{x - 1}}{4 \cdot {5}^{x - 1}} = 14⋅5x−15x−5x−1=1
5x−5x−14⋅5x−1=5x51−x5\frac{{5}^{x} - {5}^{x - 1}}{4 \cdot {5}^{x - 1}} = \frac{5^{x} 5^{1 - x}}{5}4⋅5x−15x−5x−1=55x51−x