Is (2,1) a solution to this system of equations?
8x+7y=11
x+y=3
MathBot Answer:
False, $\left( 2, \ 1\right)$ is not a solution of $8 x + 7 y = 11 \text{ and } x + y = 3$.
$$\begin{gathered}8 x + 7 y = 11\\8 \left(2\right) + 7 \left(1\right) \stackrel{?}{=} 11\\23 \neq 11\end{gathered}$$$$\begin{gathered}x + y = 3\\2 + 1 \stackrel{?}{=} 3\\3 = 3\end{gathered}$$