(x+2)+(x+8)2\frac{(x+2)+(x+8)}{2}2(x+2)+(x+8) x (x-1)
asked by guest on Mar 19, 2025 at 4:42 pm
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x+2+x+82x(x−1)=x(2x+10)(x−1)2\displaystyle \frac{x + 2 + x + 8}{2} x \left(x - 1\right) = \frac{x \left(2 x + 10\right) \left(x - 1\right)}{2} 2x+2+x+8x(x−1)=2x(2x+10)(x−1)
x+2+x+82x(x−1)=x3+4x2−5x\frac{x + 2 + x + 8}{2} x \left(x - 1\right) = x^{3} + 4 x^{2} - 5 x2x+2+x+8x(x−1)=x3+4x2−5x