Is (–10, –6) a solution to this system of inequalities?

6x − 11y ≤ –3

3x − 4y ≤ –6

asked by guest
on Mar 29, 2025 at 7:06 pm



MathBot Answer:

False, (−10, −6)\left( -10, \ -6\right) is not a solution of 6x−11y≤−3 and 3x−4y≤−66 x - 11 y \leq -3 \text{ and } 3 x - 4 y \leq -6.

6x−11y≤−36(−10)−11(−6)≤?−36≰−3\begin{gathered}6 x - 11 y \leq -3\\6 \left(-10\right) - 11 \left(-6\right) \stackrel{?}{\le} -3\\6 \nleq -3\end{gathered}3x−4y≤−63(−10)−4(−6)≤?−6−6≤−6\begin{gathered}3 x - 4 y \leq -6\\3 \left(-10\right) - 4 \left(-6\right) \stackrel{?}{\le} -6\\-6 \le -6\end{gathered}

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