Math Problem Solver

$\frac{2}{3} - \frac{2\frac{1}{2}}{4} \approx 4.16666666666666666666667 \cdot 10^{-2}$

An operation occurred where the result is not representable with a finite number of digits, regardless of precision, so an approximation was made.

Steps

1. "Convert" $2$ to standard form by writing it in standard form notation $\left(2 \cdot 10^{0}\right)$.

2. "Convert" $3$ to standard form by writing it in standard form notation $\left(3 \cdot 10^{0}\right)$.

3. Divide $2 \cdot 10^{0}$ by $3 \cdot 10^{0}$ by dividing their bases and subtracting their exponents to produce approximately $6.666666666666666666666667 \cdot 10^{-1}$.

4. "Convert" $-1$ to standard form by writing it in standard form notation $\left(-1 \cdot 10^{0}\right)$.

5. "Convert" $2$ to standard form by writing it in standard form notation $\left(2 \cdot 10^{0}\right)$.

6. Use long division to evaluate $\frac{1}{2}$, resulting in $5 \cdot 10^{-1}$.

7. Add $2 \cdot 10^{0}$ to $5 \cdot 10^{-1}$, producing $2.5 \cdot 10^{0}$, by shifting the right-hand side down 1 place to make the exponents the same.

8. "Convert" $4$ to standard form by writing it in standard form notation $\left(4 \cdot 10^{0}\right)$.

9. Divide $2.5 \cdot 10^{0}$ by $4 \cdot 10^{0}$ by dividing their bases and subtracting their exponents to produce $6.25 \cdot 10^{-1}$.

10. Multiply $-1 \cdot 10^{0}$ by $6.25 \cdot 10^{-1}$ by multiplying their bases and adding their exponents to produce $-6.25 \cdot 10^{-1}$.

11. Subtract $6.25 \cdot 10^{-1}$ from $6.666666666666666666666667 \cdot 10^{-1}$, producing $4.16666666666666666666667 \cdot 10^{-2}$.